for 4.99s if it (5 pts) Calculate the final speed of a body that experiences +1.

Question

for 4.99s if it (5 pts) Calculate the final speed of a body that experiences +1.52 acceleration had +3.00 - initial velocity (in the same direction as the acceleration). Vi- Vo +aavto V 10.58mls 3.00+0.5 m/s 4.9q s) a. (5 pts) Calculate the distance over which a body eperiencing constant +1.52 acceleration acquires +3.00velocity if it starts from rest.Vo +2aay (x,Xo 3 0 + 2 (1.52 %-XX, 9.00-3.04(x, 2.86 m (5 pts) Calculate the time it takes for a diver on Earth to land in a pool 2.20 m below the point where she jumps off a diving board with initial velocity in the y-direction of +2.29 . o Vo s (5 pts) Same situation as the previous proble..at what two times is her speed 1.58

Explanation / Answer

5) Her speed can be 1.58 m/s when her velocity is 1.58 m/s in upward direction or - 1.58 m/s in upward direction.

1.58 = 2.29 - gt1

t1 = (2.29-1.58)/9.81

= 0.0724 s

Now t2 = (2.29 - - 1.58)/9.81

= 0.3945 s

Hence the two times are 0.0724s and 0.3945s.

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