(5 points) Remember, your complete worked solution is due on test day. It must i

Question

(5 points) Remember, your complete worked solution is due on test day. It must include all calculations and a scale drawing. Three source charges are used to create an electric field at a point P in space located at x = 3 m, y = 4 m. The first charge is 6aand is located at the ongin. The second charge is 121C and is located on the x-axis at x = 2 m. The third charge is-141C and is located on the y-axis at y = 2 m. The x-component of the electric field at point P is N/C The y-component of the electric field at point P is N/C The electric potential (or voltage) at the point P is N/C. A new charge of-12uC is now placed at the point P The x-component of the electric force on the new charge due to the original three charges is N. The y-component of the electric force on the new charge due to the original three charges is N. The potential energy of the new charge due to the original three charges is

Explanation / Answer

P = (3, 4)

s1 = (0, 0) , s2= (2,0) , s3 = (0, 2)

E = k q r / |r|

r1 = 3i + 4j

|r1| = sqrt(3^2 + 4^2) = 5

E1 = (9 x 10^9)(6 x 10^-6)(3i + 4j) / 5^3

E1 = 1296i + 1728j N/C

r2 = i + 4j , |r2| = 4.123

E2 = 1541i + 6164j N/C

r3 = 3i + 2j , |r3| = 3.61

E3 = -8065i - 5376j N/C

E = E1 + E2 + E3 = -5228i + 2515j

X - component = - 5228 N/C

y - component = 2515 N/C

potential = kq1/r1 + kq2/r2 + kq3/r3

= 2091.5 Volt

Fx = q Ex = 62.7 x 10^-3 N

Fy = q Ey = - 30.2 x 10^-3 N

potential energy = q V = - 0.025 J

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.