(12%) Problem 8: Consider the circuit in the diagram, with sources of emf listed

Question

(12%) Problem 8: Consider the circuit in the diagram, with sources of emf listed ul Randomized Variables 61 24 V 0.10 Ri 5.0 20 63-11 V 64-31 V 10.50 40 0.20 78 9 i 0.05 h ©theexpertta.com 33% Part (a) Find 11 in amps Grade Summary Deductions 0% Potential 100% Submissions Attempts remaining: 7 (0% per attempt) detailed view cotanOasin) acosO atanO acotansinh0 coshO tanhO cotanh0 0 END °Degrees -Radians 4o Submit Hint I give up! Hints: 2% deduction per hint. Hints remaining Feedback: 2% deduction per feedback - 33% Part (b) Find 12 in amps. 33% Part (c) Find 13 in amps.

Explanation / Answer

from the given circuit
E1 = 24 V
E2 = 47 V
E3 = 11 V
E4 = 31 V

So using Kirchoff's voltage Law in the top and the bottom loops
E1 = I1(0.1 + 20 + 5) - I2(40 + 0.5) + E2
=> I1(25.1) - I2(40.5) + 23 = 0

E2 = I2(0.5 + 40) + (0.2+0.05+78)I3 + E4 - E3
=> I2(40.5) + I3(78.25) - 27 = 0

also from kirchoff's junction law

I1 + I2 - I3 = 0

solving these
I1 = -0.2663 A
I2 = 0.40285 A
I3 = 0.136 A

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