I need #4 and if you can do number(#2) I am grateful. I don\'t need number 3 2)
ID: 1657741 • Letter: I
Question
I need #4
and if you can do number(#2) I am grateful.
I don't need number 3
Explanation / Answer
2) LET DEPTH OF THE well be d
then time taken for the coin to reach the bottom = t1
time taken by sound to come back = t2
d = 0.5gt1^2
t1 = sqrot(2d/g)
and t2 = d/v
where v is speed of sound in air, v = 1120 ft/s
hence t1 + t2 = 3 = sqroot(2d/32.2) + d/1120
3360 - d = 279.129*sqroot(d)
11289600 + d^2 - 6720d = 77912.998641*d
d^2 - 84632.998641d + 11289600 = 0
solving for d
d = 133.60 ft
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.