Main Menu Course Contents l Course Contents» »Hw4 Notes Bookmark Evaluate-Commun

Question

Main Menu Course Contents l Course Contents» »Hw4 Notes Bookmark Evaluate-Communicate-Print Info (8c4p18) The velocity v of a particle moving in the xy plane is given by v = (8.0t-4.0t*)i + 7.5j, in m/s. Here v is in m/s and t (for positive time) is in s. What is the acceleration when t = 3.0 s? i-component of acceleration? Subm AnawerTries 0/12 j-component of acceleration? Submit Answer Tries 0/12 When (if ever) is the acceleration zero (enter time in s or 'never)? Submia AnswerTries 0/12 When (if ever) is the velocity zero (enter time in s or 'never)? Subnat AnswerTries 0/12 Post Discussion Send Feedback

Explanation / Answer

a = dv/dt

a = d/dt{( 8.0t – 4.0t2)i + 7.5 j} m/s

a = (8 – 8t) i m/s2

Part A:

Acceleration when t = 3s

a = (8- 24)I m/s2

a = -16 i m/s2

Part B

there is no j component so a = 0 j m/s2

Part C:

Let a = 0

(8 – 8t) i = 0

t = 1 s

PART D:

Never, since vy = 8.0 m/s at a minimum

Related Questions

Navigate

• Browse (All)
• Browse M
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.