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https//session.masteringphysics.com/myct/mastering Jassignment/list/5539367 9 https//session masteringphysics.com/myct/itemView?offset-next&assignmentProblemiD-82238682; Che 2.W Problem 2.25 Problem 225 Part A On your wedding day you leave for he church 290 minutes before the ceremony is to begin, which shouid be plenty of time since the church is only 12.0 miles away. On the way however you have to make an unantcipated stop tor construction work on the road. As a result your average speed for the frst 14 0 minutes is only 50 ml/h. What average speed do you need foe the rest of the tho to get you to the chuech on ime? 10.42 Incorrect; One attempt remaining: Try Again

Explanation / Answer

Given that,

Total distance = 12 mi

total time = 29 min

Distance traveled in first 14 min = 5 * (14/60) = 1.16 mi

remaining distance d = 12 - 1.16 = 10.83 mi

remaining time , t = 29 - 14 = 15 min

Average speed neeaded,

Vavg = d / t

Vavg = 10.83 / (15/60)

Vavg = 43.33 mi/h

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