can you please provide how you got the answer so i would understand!! thank you
ID: 1657438 • Letter: C
Question
can you please provide how you got the answer so i would understand!! thank you in advance
3. Two wires carrying equal currents exert a force Fo on each other. (a) The current in each wire is doubled, while the distance of separation remaining constant. What is the magnitude of the force that one wire exerts on the other? (b) When a magnetic field is parallel to a current-carrying wire, what is the force on the wire? (15 pts) 4. The magnetic force exerted on a 1.650 m straight wire is 1.975 N. The wire carries a current of 5.30 A in a region with constant magnetic field of 0.250 T. what is the angle between the wire and the magnetic field? (15 pts) 5. A copper rod 0.570 m long and with a mass 0.05900 kg is suspended from two thin wire. At right angle to the rod is a uniform magnetic field of 0.670 T pointing into the page. Find (a) the direction and (b) magnitude of the electric current to levitate the copper rod's gravitation force. (20 pts)Explanation / Answer
3.
F0=µ0I1I2L/2r
Where F0=Magnetic force exerted by one wire on other
I1 = Current in first wire
I1 = Current in second wire
L= Length of wire
r=distance between wire
a)
F’= µ0I1’I2’L/2r
Put I1’= 2I1
I2’= 2I2
F’= µ0*2I1*2I2*L/2r
F’= 4*µ0I1I2L/2r
F’=4F0
After doubling the current force will be four times greater than initial force.
b)
Fmagnetic=IBLsin
Where i= Current in wire,L=length of wire, B= magnitude of magnetic field, =angle between magnetic field and wire
Plug =0 deg
Fmagnetic=IBLsin0
Fmagnetic= 0 N
The magnetic force will be zero.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.