Part A A 2.0-kg box rests on a plank that is inclined at an angle of 65° above t

Question

Part A A 2.0-kg box rests on a plank that is inclined at an angle of 65° above the horizontal. The upper end of the box is attached to a spring with a force constant of 360 N/m , as shown in the figure(Figure 1) If the coefficient of static friction between the box and the plank is 0.21, what is the maximum amount the spring can be stretched and the box remain at rest? Express your answer using two significant figures A2op 2.5 cm Submit My Answers Give Up Incorrect Try Again; 3 attempts remaining Provide Feedback Continue Figure 1 of 1 2.0 kg 65°

Explanation / Answer

Let us consider the forces acting on the block

component of weight of block along incline = 2*9.8*sin65 = 17.76 N

Normal force from plane on block = 2*9.8*cos65 = 8.28 N

Friction force on block = 0.21*8.28=1.74 N

Spring force = 360x (where x is elongation of spring)
360x = 17.76-1.74 = 16.02

x = 16.02/360 = 0.0445m = 4.45 cm

Answer is 4.45 cm

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