For this problem concerning Kirchhoff: junction rule and loop rule, refer to the

Question

For this problem concerning Kirchhoff: junction rule and loop rule, refer to the figure. (Assume that R1-3.5 , R2-5.7 , R3-5.0 , and V-2.0 V.) R2 Ww ) Notice that there are two loops, labeled 1 and 2 in this circuit. Does it matter that there is no battery in loop 1, but only two resistors? Explain. Yes, A battery is necessary to allow the current to flow. No. A lcop can have any number of batteries, including none at all. (u) Tha currents through the thras reaiato ar labelad a i 2, and i3. Does it matter which dirscion, laft-to-right or right-to-laft, ha baan chozen for sach circuit? O Yes. If we choose the wrong direction, it wrill affect the magnitude of the currents No. If w. choose the wrong direction, it will only affect the sign of the answer. (ili When re place and sians on the end of each resitor, does it matter which side is and which is-? Yes. Once we've made our choice for the direction of the currents, if we chaose the wrong placement ofand - it will affect the magnitude of the currents. O No. Once we've made our choice for the direction of the currents, if w choose the wrong placement of+ and-, it will only affect the sign of the answer. (iv) When we evaluate the potentiel drops and rises around a closed loop, does it matter which direction, clockwise or counterclockwise, is chosen for the evelustion? Yes No Use Kirchhoffs junction and loop rules to determine the currents through the three resistors. (Due to the nature of this problem, do not use rounded intermediate velues in your calculetions-including answers submitted in WebAssign. Indicate the direction with the sign of your enswer) 42-

Explanation / Answer

(i)

No.A loop can ave any number of natteries .including none at all

(ii)

No.If we chooose the wrong direction , it will onlyaffect the sign of the answer

(iii)

No. once we've made our choice direction of current,if wechoose the wrong placement of + , - it will affect the sign of the answer

iv)

no

calculation

for loop 1

-R1*I1 - I2*R2 = 0

-3.5I1 - I2*5.7 = 0 ..........(1)

for loop2

-I3*R3 + v - I2*R2 = 0

-I3*5 + 7 - I2*5.7 = 0...........(2)

applying kirchoff junction law

at pointC

I1 + I2 = I3 ........(3)

solving 1 , 2 , 3

I1 = -4.45 A

I2 = 2.74 A

I3 = -1.72 A

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