A hiker walks 1.80 km south and then 2.25 km east, all in 3.20 hours. HINT (a) C

Question

A hiker walks 1.80 km south and then 2.25 km east, all in 3.20 hours. HINT (a) Calculate the magnitude (in km) and direction (in degrees south of east) of the hiker's displacement during the given time. magnitude288 km direction south of east (b) Calculate the magnitude (in km/h) and direction (in degrees south of east) of the hiker's average velocity during the given time. magnitude direction v km/h X ° south of east (c) What was her average speed (in km/h) during the same time interval? X km/h Need Help?

Explanation / Answer

r1 = - 1.80j km

r2 = 2.25i

r = r1 + r2 = 2.25i - 1.80j km

(A) magnitude = sqrt(2.25^2 + 1.80^2) = 2.88 km

theta = tan^-1(1.80 / 2.25) = 39 deg

(B) average velocity = displacement / time

magnitude = 2.88 / 3.20 = 0.9 km/h

direction = 39 deg

(same direction as displacement)

(c) average speed = distance / time

= (1.80 + 2.25) / 3.20

= 1.26 km/h

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