(1090) Problem 8: Suppose a 68-kg mountain climber has a 0.34 cm diameter nylon
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(1090) Problem 8: Suppose a 68-kg mountain climber has a 0.34 cm diameter nylon rope Randomized Variables m=68 kg d= 0.84 cm l=37m D A By how much does the mountain climber stretch her rope,in centimeters, when she hangs 37 m below a rock outcropping? Assume the Young's modulus of the rope is 5 x 109 N/m2 Grade Summa Deductions Potential 0% 100% cos0 tan() | acosO Sin Submissions ts remaining:5 cotana asin0a (5% per attempt) detailed view atan acotan sinhO cosh0 anh cotanhO Degrees O Radians END Submit Hint I give up! Hints: -deduction per hint. Hints remaining: 3 Feedback: 5% deduction per feedback.Explanation / Answer
young's modulus = stress / strain
stress = force / area
force = weight of climber
force = 68 * 9.8 N
stress = 68 * 9.8 / (pi * (0.84 / 2)^2)
strain = change in length / length
strain = change in length / 37
5 * 10^9 = 68 * 9.8 / (pi * (0.84 * 10^-2 / 2)^2) / (change in length / 37)
change in length = 0.08898 m
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