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ver of a car going 25 m/s sees a hippo in the road 36 m ahead. It takeg 0.6 s to

ID: 1656859 • Letter: V

Question

ver of a car going 25 m/s sees a hippo in the road 36 m ahead. It takeg 0.6 s to apply the brake, and the maximum deceteration is 15 m/s the ariver Determine if the car hits the hippo. (SHOW WORK) What is the maximum speed at which the car in the previous problem could be. moving and not collide with the barrier? (SHOW WORK) 5.) A 0 m-long train accelerates from rest. If the front of the train passes aman 250 m down the track at a speed of 52 m/s, what will be the speed of the last car as the train passes the man? 8 A stone is dropped from a 98 m builaing. Two seconds later a second stone is thrown straight down at 32 m/s. How fast is the second stone moving when the first stone hits the ground? 7. A sportscar is advertised to be able to-stop, from a speed of 68 m/s within distance of.155 m. What is the acceleration during this time? How far does a plane fly while being decelerated from 145 m/s to 75 m/s in 45 s? 9. A rock is thrown straight up from a 75 m cliff with a speed of 25 m/s Bow fast does it hit the ground? How much time does this take? 0. A rock is thrown straight up from a 98 m cliff with a speed of 15 m/s. How far below the cliffis the rock after 6 seconds? 11. A baseball is hit at 30 m/s at an angle of 60°. Immediately an outfielder runs with constant speed 6 m/s toward the infield and barely catches the ball. Baw far from the plate was the outfielder? 12. A car is found in a ditch 32 m away from the bottom of a cliff. If the 13. An arrow is shot at a 52° angle with a speed of 39 m/s. How far does it 14. A Stone is dropped from a tall cliff. Four seconds later a second stone cliff is 86.4 m high, how fast was the car traveling? go, and how high? is thrown straight down with a speed of 42 m/s. If they both hit the ground at the same time, how high is the cliff?

Explanation / Answer

3] Total distance covered by the car will be:

S = ut + [(v2 - u2)/2a]

=> S = (25 x 0.6) + [(0 - 252)/2(-15)] = 35.833 m

Since the hippo is at S' = 36 meters, the car just stops before hitting it.

4] S = ut + [(v2 - u2)/2a]

take S = 36m

then, 36 = 0.6u + (u2/30)

=> 0.0333u2 + 0.6u - 36 = 0

multiply by 30 on both sides to get:

=> u2 + 18u - 1080 = 0

solve this quadratic to get: u = 25.073 m/s and u = - 43.073m/s

therefore, the maximum speed of the car can be 25.073m/s.