DYNAMICS OF A ROLLING CART A cart (mass Mi) is pulled on a horizontal track by a
ID: 1656748 • Letter: D
Question
DYNAMICS OF A ROLLING CART A cart (mass Mi) is pulled on a horizontal track by a string that passes over a Smart Pulley and is attached to a weight (mass M2) as shown in the sketch. The rolling friction force of the car t is f, and the resulting acceleration of each mass is a. M1 42: QUESTIONS 1. Apply Newton's laws to each mass and combine these to deduce the formula (Mi+ M2) a-M2 g-f The experimental data will be the measurements of accelerations a of the total mass for few values of M2. You will plot the product (MM2 a (y-axis against M2 (x-axis) to obtain a straight line. Explain how the free fall acceleration 2. g and friction force fcan be obtained from this straight line graph.Explanation / Answer
(A)
Let T = tension in the cord
For motion of M2 kg block downwards,
M2g - T = M2a
and for the motion of M1 kg block upwards,
T - F = M1a
Adding the 2 equations we get :
M2g - T + T - F = M1a + M2a
(M1 + M2)*a = M2*g - F
(B)
Please perform the experiment to plot the graph.
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