1. A circular loop of wire with a diameter of 0.626 m is rotated in a uniform el
ID: 1656567 • Letter: 1
Question
1. A circular loop of wire with a diameter of 0.626 m is rotated in a uniform electric field to a position where the electric flux through the loop is a maximum. At this position, the electric flux is 7.50 x 10*N m2/C. Determine the magnitude of the electric field. A) 6.00×106 N/C B) 8.88 × 105 N/C C) 1.07 x 106 N/C D) 2.44 × 106 N/C E) 4.24 x 106 N/C 2·The force exerted by a uniform electric field on a dipole is: A) B) C) D) E) perpendicular to the electric field parallel to the dipole moment zero parallel to the electric field perpendicular to the dipole momentExplanation / Answer
1. At the point of maximum flux, the electric field is directed normal to the plane of the circular loop.
The electric flux may be calculated as,
Flux, F = E*A
Where, we assume that the electric field, E, is uniform over the area of the circle, A.
We may solve for an unknown electric field magnitude as,
E = F / A
Where we are told that the flux is: F = 7.5"10^5 N m^2 / C,
and we can calculate the area of the loop as,
A = * (D/2)^2
A = (3.1415) * (0.626 m / 2)^2 = .308 m^2
Therefore,
E = (7.5*10^5 N m^2 / C) / (.308 m^2)
E = 2.43*10^6 N/C
Answer
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