Electric Potential and Potential Energy Part A A particle with charge 4.80x10-19

Question

Electric Potential and Potential Energy Part A A particle with charge 4.80x10-19 C is placed on the x axis in a region where the electric potential due to other charges increases in the +x direction but does noft change in the y or z direction. The particle, initially at rest, is acted upon only by the electric force and moves from point a to point b along the x axis, increasing its kinetic energy by 4.80×10-19 J·In what direction and through what potential difference V,-V, does the particle move? Hints The particle moves to the left through a potential difference of V Va1.00 V The particle moves to the left through a potential difference of V - Va-1.00 V The particle moves to the right through a potential difference of Vb-= 1.00 V The particle moves to the right through a potential difference of Vb-V,--1.00 V The particle moves to the left through a potential difference of V,-V, 10.0 V The particle moves to the right through a potential difference of Vb-V, -10.0 V Submit My Answers Give Up Part B If the particle moves from point b to point c in the y direction, what is the change in its potential energy, Ue-Ub? Hints +4.80*10-19 J - 4.80x10-19 J

Explanation / Answer

change in electrical potential energy = -(change in kinetic energy)
q(V) = -K
q(Vb - Va) = -K
q(Va - Vb) = K
(4.80*10^-19 C)(Va - Vb) = 4.80*10^-19 J
Va - Vb = 1.00 V

Vb - Va = -1.00 V the particle move to the left

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