The two plates of a capacitor are charged by a battery. The plates are then disc
ID: 1656384 • Letter: T
Question
The two plates of a capacitor are charged by a battery. The plates are then disconnected from the battery and pulled apart so that their separation is doubled. Explain how each of the following quantities changes: the capacitance of the capacitor, the charge on the capacitor plates, the voltage across the plates, and the energy stored in the capacitor. Justify each answer. The two plates of a capacitor are charged by a battery. The plates are then disconnected from the battery and pulled apart so that their separation is doubled. Explain how each of the following quantities changes: the capacitance of the capacitor, the charge on the capacitor plates, the voltage across the plates, and the energy stored in the capacitor. Justify each answer. The two plates of a capacitor are charged by a battery. The plates are then disconnected from the battery and pulled apart so that their separation is doubled. Explain how each of the following quantities changes: the capacitance of the capacitor, the charge on the capacitor plates, the voltage across the plates, and the energy stored in the capacitor. Justify each answer.Explanation / Answer
According to the given problem,
a)The capacitance of the capacitor,
C = 0A/d where d is separation
so as d doubles the capacitance of the capacitor reduces by half
b) Q = CV where v is volatage
Now, V is contant so Q reduces by half
c)the voltage across the plates remains contant.
d) E = 1/2 CV2 as the volatege remains contant E reduces to half .
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