Alternative Exercise 3.102 Two tanks are engaged in a training exercise on level

Question

Alternative Exercise 3.102 Two tanks are engaged in a training exercise on level ground. The first tank fires a paint-filled training round with a muzzle speed of 246 m/s at an angle 12.6 above the horizontal while advancing toward the second tank with a speed of 15.0 m/s relative to the ground. The second tank is retreating at a speed of 35.5 m/s relative to the ground, but is hit by the shell. You can ignore air resistance and assume the shell hits at the same height above ground from which it was f Part A ired Find the distance between the tanks when the round was first fired. Submit Give Up Part B Find the distance between the tanks at the time of impact.

Explanation / Answer

b) Initial vertical velocity vy = 246 * sin 12.6 = 53.66

t = 53.66 / 9.81 = 5.47 s

Total flight time = 2 t = 2 * 5.47 = 10.94 s

horizontal velocity vx = 246 * cos 12.6 = 240.1 m/s

d = vx * 2 t = 240.1 * 10.94

distance between the tanks at time of impact d = 2626 m

a) v = 35.5 - 15 = 20.5 m/s

d = 20.5 * 10.94 = 224.27 m

distance between the tanks when the round was fired = 2626 - 224.27

d = 2402 m

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