Problem 22.33 A-10 nC charge is located at (, v) 1.2 em,0 m) Part A What is the-

Question

Problem 22.33 A-10 nC charge is located at (, v) 1.2 em,0 m) Part A What is the-component of the electric field at the position (z.3)s (4.4 cm·0 cm)? Express your answer to two significant figures and include the appropriate units. E-Value Units Submit My Answers Give UR Part B What is the-component of the electric field at the position (z.) (4.4 cm , 0 cm)? Express your answer to two significant figures and include the appropriate units. E, . | Value Units Submit My Answers Give Up Part C What is the -component of the electric field at the position (, v)--4.4em, 0 em)? Express your answer to two significant figures and include the appropriate units. EValue Units Submit My Answers Give Up Part D What is the -component of the electric field at the position (, )(-4.4em, 0 em)? Express your answer to two significant figures and include the appropriate units. E, Value Units Submit My Answers Give Up Part E What is the -component of the electric field at the position (, ) (0em, 4.4 em )? Express your answer to two significant figures and include the appropriate units. EVaue Units

Explanation / Answer

E = kq/r^2

a) E = 9 x 10^9 (-10 x 10^-9) / (r^2) ( r= 4.4-1.2= 3.2 x10^-2)

E = (-90 ) / (0.001024) = 8.79 x 10^4 N/C

b) E = 0 ( along y axis)

c)E = 9 x 10^9 (-10 x 10^-9) / (r^2) ( r= 4.4 + 1.2=0.056m)

E = -90 / (0.056)^2=2.87 x 10^4 N/C

d)0

e)distance between charge and y axis = sqroot (1.2^2 + 4.4^2) = 0.045 m apprx

angle= tan^-1 ( 4.4/1.2)=74.74 degree apprx

Ex = 9 x 10^9 x 10 x 10^-9 cos 74.74 / ( 0.045 )^2= 1.17 x 10^4 N/C

Ey =  x 10^9 x 10 x 10^-9 sin 74.74 / ( 0.045 )^2 = 4.29 x 10^4 N/C

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.