Ball 1 is dropped from rest from a height of 15 m off the ground. At the same ti

Question

Ball 1 is dropped from rest from a height of 15 m off the ground. At the same time, ball 2 is thrown upward with an initial velocity of 10 m/s from the ground. 1. At what height do the balls collide? 2. Is ball 2 rising or falling when the two balls collide? Why? Ball 1 is dropped from rest from a height of 15 m off the ground. At the same time, ball 2 is thrown upward with an initial velocity of 10 m/s from the ground. 1. At what height do the balls collide? 2. Is ball 2 rising or falling when the two balls collide? Why? 1. At what height do the balls collide? 2. Is ball 2 rising or falling when the two balls collide? Why?

Explanation / Answer

here,

initial speed for the seccond ball ,u2 = - 10 m/s

let the time taken before they collide be t and vertical distance be y

for the first ball

y = 0 + 0.5 * g * t^2 ...(1)

and

for the seccond ball,

y = u2 * t + 0.5 * g * t^2

- (15 - y) = - 10 * t + 0.5 * 9.81 * t^2 ....(2)

from (1) and (2)

t = 1.5 s

y = 11 m

a)

they collide at ( 15 -y = 4 m)

b)

after t = 1.5 s

the ball 2 is falling

so , they will collide when the ball 2 is falling

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