hree Dimensions (a) Wh velocit 94 CHAPTER 3 Motion in Two or T The hampion Jumpe

Question

hree Dimensions (a) Wh velocit 94 CHAPTER 3 Motion in Two or T The hampion Jumper of the Insect World. is the world record for insectter lea jumps. When leaping at an angle of 58.0° above the horizont some of the tiny critters have reached a maximum height of 58.7 cm 3.20 above the level ground. (See Nature, Vol. 424, July 31, 2003, p. 509) (a) What was the takeoff speed for such a leap? (b) What horizontal distance did the froghopper cover for this world-record leap? 3.15 .. Inside a starship at rest on t top of a horizontal table and lands a distance D from the foot of the table. This starship now lands on the unexplored Planet X. The commander, Captain Curious, rolls the same ball off the same C froghopper, Philaenus spumarius, hold water -l as it tion. the w resis (a)F high the it h he earth, a ball rolls off the table with the same initial speed as on earth and finds that it lands a distance 2.76D from the foot of the table. What is the accelera- tion due to gravity on Planet X? 3.2 resistance. (a) Find the horizontal and vertical components of the he (d) How far from its firing point does the shell land? (e) At its th 3.16 On level ground a shell is fired with an initial velocity of th 40.0 m/s at 60.0° above the horizontal and feels no appreciable air th shells initial velocity. (b) How long does it take the shell to reach ro its highest point? (c) Find its maximum height above the ground. ft highest point, find the horizontal and vertical components of its acceleration and velocity 3.17 A major leaguer hits a baseball so that it leayes the hat at a speed of 300 m/s ond

Explanation / Answer

3.14 :

(A) Suppose take off speed is v0 then

initial vertical velocity, v0y = v0 sin58

ay = -9.8 m/s^2

y = 0.587 m

Applying vfy^2 - v0y^2 = 2 a y

0^2 - (v0 sin58)^2 = 2 x -9.8 x 0.587

v0 = 4 m/s

(b) when it comesback to same vertical level

then vertical diplacement, y = 0

Applying y = v0y t + a t^2 / 2

0 = (4 sin58) t - 9.8 t^2 /2

t = 0.69 sec

Horizontal distance = (4 cos58) (0.69)

= 1.47 m

Related Questions

Navigate

• Browse (All)
• Browse H
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.