can you show me how to do q2 ) During the inhutesimal tine nter i resistor? (ii)

Question

can you show me how to do q2

) During the inhutesimal tine nter i resistor? (ii) What is the total energy lost in the resistor during the entire discharging process Is your answer sensible? Explain. ) When a capacitor is charged through a resistor the current at time t is given by and the final charge on the capacitor will be Qr Ce. () Calculate the total work done by the battery during the charging process. Express your answer in terms of Qr. Is your answer sensible, given the definition of emf? Explain. (ü) What fraction of the work done by the battery ends up being stored as potentia energy in the capacitor? Where did the rest go? uestion 2 (a) What will the final charge on the 1 F capacitor be? 1.00 8.00) 1.00 F (b) Suppose the battery is now removed 10.0 and the capacitor begins to discharge How long will it take for the capacitor to lose half of its original stored energy? 1.00 2.00 Question 3 25,0

Explanation / Answer

2a) current will not flow into capacitor and whatever current flows through 1 ohm resistor will flow in 4ohm resistor.

And we know that for same current in series, the potential difference is proportional to resistance.

Hence Voltage at left end of capacitor =10*4/(4+1) = 8V

Similarly voltage at right end of capacitor = 10*2/(8+2) = 2V

Potential across capacitor = 8-2 = 6V

Charge = CV = 1*6 = 6 C answer

B) Equivalent resistance = (4+2)*(8+1)/((4+2)+(8+1)) =3.6ohm,

energy = 0.5CV^2

So energy will become half if the voltage becomes 1/sqrt2 =0.707 times

V = Vo * e^(-t/RC)

0.707 = e^(-t/3.6*1)

ln 0.707 = - t/3.6

t = - 3.6 * ln 0.707

= 1.248 s answer

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