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Part A Secure https session.masteringphysics.com/myct item ew?assignmentproblemI

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Question

Part A Secure https session.masteringphysics.com/myct item ew?assignmentproblemID: 8356M31&offset.next; gPhys Chapter2 Problem 2.8 rses previous | 2 of 13 I ned Home Problem 2.8 Part A In college softball, the distance from the pitcher's mound to the batter is 43 feet If the ball leaves the bat at 85 mph, how much time elapses between the hit and the ball reaching the pitcher? Express your answer to two significant figures and include the appropriate units ments Tools tValueUnits Area Submit My Answers Give Up ettings 14201

Explanation / Answer

Given,

85 mph = 85*0.447 m/s = 37.995 m/s

( 1mph = 0.447 m/s)

43 feet = 43*0.305 m = 13.115 m

We know that,

Distance = Speed*Time

Time = Distance/Speed

Time, t elapses between the hit and the ball reaching the pitcher

t = 13.115/37.995 = 0.345 s

Answer

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