Our calculation of plate separation assumes simple flat parallel deflection plat

Question

Our calculation of plate separation assumes simple flat parallel deflection plates. In practice, the deflection plates actually have a flared end. Given this information, what do the measured values of the plate separation distance that you calculated in step 15 actually represent? Explain your reasoning. A free electron and a free proton are placed in identical electric fields. Compare the electric forces on each particle and discuss their subsequent accelerations. Suppose the force of gravity on the electron was comparable to the electric force created by the deflection plates. How would this change the results of your experiment?

Explanation / Answer

Only answer 2 can be given.

F=qE.

Now for an electron the charge is negative and for a proton charge is positive. But the magnitude of the charge in both the case is same. So the magnitude of the force exerted will be same but the direction will be different.

Now acceleration is inversely proportional to mass. So acceleration of electron will be more as it's mass is less.

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