Home Stu Class Management I Help ETA Problem Set 4 Begin Date:9/11/2017 4:00:00

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Home Stu Class Management I Help ETA Problem Set 4 Begin Date:9/11/2017 4:00:00 PM-Due Dat e: 9/182017 4:00:00 PM End Date: 12/82017 11:0000 PM m 5: While competing in the long jump, a person leaps over a smooth horizontal sand surface. She lands on the (13%) Proble surface with speed v 5.5 ms at an angle e-38 below horzontal. Assume that the person moves wthout air resistance Use a Cartesian coordinate system with the origin at her final position The posit position, and the positive y-axis is directed vertically upwards ve x-axis is directed from her initial to her final A 33% Part (a) Express the jumpers initial velocity vector in rectangular form vo in terrns of v, g, and the unt vectors i and j Grade Summary Deductions 096 Potential 100 Submissions Attempts remaining (290 per attempt) sin(a) sin ) sin(e) 4 5 6 detailed view Submit Hint I give up! Hints:29-deduction per hint Hints remaining:- Feedback: 09% deduction per feedback 33% Part (b) Calculate the maximum height, hmax in meters, the Jumper reaches above ground level 33% Part (c) What horizontal distance from the impact position, x0 in meters, did theyumper begin her long jump? All content 2017 Expert T.A.LLC

Explanation / Answer

Here,

a)

vf = 5.5 m/s

theta = 38 degree

part a) for the initial velcity of jumper

v = vf * cos() i + vf * sin() j

part b)

Hmax = (vf * sin(theta))^2/(2g)

Hmax = (5.5 * sin(38 degree))^2/(2 * 9.8)

Hmax = 0.585 m

b) for the horizontal distance

horizontal distance = (5.5^2 * sin(2 * 38 degree))/9.8

horizontal distance = 3 m

the horizontal distance is 3 m

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