Delta x = vt a = v_f -- v_0/t 2a Delta x = v^2_f - v^2_0 Delta x = v^t_0 + 1/2 a

Question

Delta x = vt a = v_f -- v_0/t 2a Delta x = v^2_f - v^2_0 Delta x = v^t_0 + 1/2 at^2 Delta x = v_f t - 1/2 t^2 That strange classmate of yours slides your physics textbook off of the lab table with a speed v. Your book meets the floor in time t. (a) Derive an equation for the height of the tabletop above the floor. (b) Write an equation for the horizontal distance the book travels from the table's edge. (c) Calculate the answers to parts (a) and (b) if the book leaves the table at 1.2 m/s, the time in the air is 0.43 s, and you don't know the mass of the book.

Explanation / Answer

a)

Using the equation of motion :

s = ut + 0.5*at^2

here , s = height of the tabletop = h

u = initial vertical velocity = 0

t = time taken to reach ground

a = g

So, h = 0 + 0.5*g*t^2

So, h = gt^2/2 <------ answer

b)

Horizontal distance traveled, R = t*v  

c)

h = 9.8*0.43^2/2 = 0.906 m <---- answer

R = 0.43*1.2 = 0.516 m <----- answer

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