A) How much charge can be placed on a capacitor which air between the plates bef

Question

A) How much charge can be placed on a capacitor which air between the plates before it breaks down if the area of each plate is 5.00cm^2?
B) Find the maximum charge is polystyrene is used between the plates instead of air. Assume the dielectric strength of air is 3.00x10^6 V/m and that of polystyrene is 24.0x10^6 V/m A) How much charge can be placed on a capacitor which air between the plates before it breaks down if the area of each plate is 5.00cm^2?
B) Find the maximum charge is polystyrene is used between the plates instead of air. Assume the dielectric strength of air is 3.00x10^6 V/m and that of polystyrene is 24.0x10^6 V/m
B) Find the maximum charge is polystyrene is used between the plates instead of air. Assume the dielectric strength of air is 3.00x10^6 V/m and that of polystyrene is 24.0x10^6 V/m

Explanation / Answer

Here ,

A) breakdown electric field of air , E = 3 *10^6 N/C

let the charge density is sigma

sigma/(epsilon_0) = E

sigma = 3 *10^6 * 8.854 *10^-12 C/m^2

sigma = 2.66 *10^-5 C/m^2

charge on each plate = sigma * area

charge on each plate = 2.66 *10^-5 * 5 *10^-4

charge on each plate = 1.33 *10^-8 C

B)

if there is polystyrene = 24 *10^6 V/m

let the charge density is sigma

sigma/(epsilon_0) = E

sigma = 24 *10^6 * 8.854 *10^-12 C/m^2

sigma = 21.2 *10^-5 C/m^2

charge on each plate = sigma * area

charge on each plate = 21.2 *10^-5 * 5 *10^-4

charge on each plate = 1.06 *10^-7 C

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