http://physics.ncat.edu/~242/Block04Notes.pdf (Use this link for Block 4 notes &

Question

http://physics.ncat.edu/~242/Block04Notes.pdf (Use this link for Block 4 notes & equations )

Answer all 5 questions please !

For DIRECTION, choose only from these: right (rightarrow), left (leftarrow), toward the top (uparrow), toward the bottom (downarrow), into the paper out of the paper UNDETERMINED (for a zero magnitude vector), or NONE (for a scalar). A coil has a magnetic dipole moment 3.3 A-m^2 into the paper (). It is in a very large uniform magnetic field 22 T out of the paper (). Find the torque the field exerts on the coil. We see the edge of a 66 turn flat circular coil of area 0.0055 m^2 in magnitude. The eye (not ours) looks along the coil's axis. "seeing" a clockwise current of 9.1 A. Find the coil's magnetic dipole moment (with our "DIRECTION" answer relative to the paper, not relative to the eye, so our answer is either right (rightarrow) or left (leftarrow)). An electron is moving to the left (leftarrow) at 2.9 times 10^8 m/s through a very large magnetic field of 22 T out of the paper (). Find the force the magnetic field exerts on the electron. A uniform magnetic field makes an angle of 56.7 with a flat surface. Thus the magnetic field makes an angle of 90.0 degree - 56.7 degree = 33.3 degree with a normal to the surface. The area of the surface is 5.55 times 10^-5 m^2. The resulting magnetic flux through the surface is 4.44 mu Wb. Calculate the magnitude of the magnetic field. A straight wire segment is 2.54 cm long and carries a large current of 99 A to the left (leftarrow) through a very large uniform magnetic field of 22 T out of the paper (). Find the force exerted by the field on the segment.

Explanation / Answer

1. u = - 3.3 A m^2 k

B = 22 T k

torque = u x B = u B sin(theta)

theta = angle between u and B = 180 deg

and sin(180) = 0

torque = 0

2. dipole moment = N I A

= 66 x 9.1 x 0.0055

= 3.3 A m^2

direction = to the right

3. q = - 1.6 x 10^-19 C

v = - 2.9 x 10^8 i

B = 22 k

F = q ( v x B)

F = 1.02 x 10^-9 N (-j)

magnitude = 1.02 x 10^-9 N

direction = downward

4. magnetic flux = B A cos(theta)

4.44 x 10^-6 = B (5.55 x 10^-5) cos33.3

B = 0.096 T

5. F = IL X B

F = 99 x 0.0254 x 22 x sin90

F = 55.3 N

upward

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