answer questios 1- 4 Iultiple Choices: There is one best answer per question. Ci
ID: 1653502 • Letter: A
Question
answer questios 1- 4
Iultiple Choices: There is one best answer per question. Circle the letter of that answer. (8 each) Which one of the following graphs correctly represents the restoring force F of an ideal spring as a function of the displacement x of the spring from its unstrained length? 1. +F +F +1 (c 2. A mass on a spring is undergoing simple harmonic motion. Which of the following statements is correct concerning the motion of this mass? (a) The object's velocity and acceleration are simultaneously zero (b) The object's acceleration is never zero. (c The object's velocity is never zero The object's velocity is zero when its acceleration is a maximum The object's maximum acceleration is equal to its maximum velocity. A spring required a force of 5.00 N to compress it 0.100 m. How much force is required to stretch the spring 0.400 m? 3. (a) 20.0N (b) 0.400 J (c) 0.600 N 4.00 J (e) 0.800 N 4. The motion of a simple harmonic oscillator is given by xlf)-(050m)cosgt) where t is in seconds What is the frequency of this oscillator? 0.50 m (b)16 Hz (c) 1.5 s (d) (/3) s1 (e) 0.67. Hz 5. A simple pendulum closely approaches simple harmonic motion provided that )it swings through a very large angle.. (b) gravity is changing over its length. its mass is always less than a gram. it swings through a very small angle (e) its length is not greater than a meter.Explanation / Answer
MCQ
1. We kn ow that the force equation is
F = -kx where the restoring forcer acts in the opposite directions
it is like the straight line equation y = mx with a positive slope m but
the equation f = - kx is like stright line equation with -ve slope curve so
the graph c correctly represents the F = -kx with slope k
2. the maximum acceleration will be at its mean position where its velocity will also be maximum there
3. spring required force for 0.1 m is 5 N ,
force required for 0.4 m is ,
F = -kx
F2/F1 = x2/x1
F2 = x2/x1*F1 = 0.4*5/0.1 = 20 N
answer is a
4. x(t) = 0.5 cos (pi/3*t)
like
x(t) = A cos (wt)
W = pi/3 = 2pi*f ==> f = W/2pi = (pi/3)/(2pi) = 1/6 Hz
answer is b
5. simple pendulum motio closely approaches SHM provided that
if it swing through a very small angle
for small agngles only we can consider sin theta = theta
so the answer is d
6
the definition or nature of the waves itself the difference
the answer is e
7 the higher the pitch of a sound wave in air
the shorter the wavelength only
the other options are not correctly suitable
1. F = 1.50 N , x = 0.172 m , F = kx ==> k = F/x = 1.50/0.172 N/m = 8.721 N/m
now
work required to stretch 0.433 m is W = 0.5*k*x^2 = 0.5*8.721*0.433^2 J =0.8175457845 J
2.l= 2.25m , T=375/100 = 3.75 s
T = 2pi sqrt(l/g)
g = 4pi^2*l/T^2
g = 4*pi^2*2.25/(3.75)^2 m/s2 = 6.3165468 m/s2
3.
v = lambda*f
= 3.2*(7/8.4) m/s = 2.67 m/s
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