The following table contains current/voltage pairs of points as determined from

Question

The following table contains current/voltage pairs of points as determined from an experiment to verify Ohm's Law. A) Use graph paper and plot these points as voltage vs. current B) Does this device follow Ohm's Law? How do you know? C) Determine the value of the resistor used in this circuit. A (20.1 plusorminus 0.2)ohm resistor is connected in parallel with a (39.9 plusorminus 0.4)ohm resistor. The resistors are connected to a (2.90 plusorminus 0.03) V battery. A) Find the equivalent resistance (including uncertainty). B) Calculate the total current in the circuit (including uncertainty). C) Determine the value of the current in each branch of the circuit (including uncertainty).

Explanation / Answer

1)(a)V(voltage) vs I(current) graph has I(current) in X axis and voltage in Y axis.

Graph is attached.

(b)We know from Ohm's law:

V = IR

The more the current and reistance the more will be voltage.

Yes the device follows the Ohm's law.

c)from Ohm's law, V = IR => R = V/I

i)R1 = -2.32/-0.227 = 10.220 Ohm

ii)R2 = -1.847/-0.18 = 10.261 Ohm

iii)R3 = -0.721/-0.07 = 10.300 Ohm

iv)R4 = - 0.203/-0.022 = 9.227 Ohm

v)R5 = 0.586/0.054 = 10.852 Ohm

vi)r6 = 1.329/0.126 = 10.548 Ohm

vii)R7 = 1.937/0.185 = 10.470 Ohm

viii)R8 = 2.680/0.258 = 10.388 Ohm

So the Avg value of resistor will be:

R = (10.22 + 10.261 + 10.300 + 9.227 + 10.852 + 10.548 + 10.470 + 10.388)/8 = 71.966/8 = 10.289 Ohm

Hence, R = 10.289 Ohm

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