I am using the formula Flux = E*A, since the E vector is the same everywhere. Br

Question

I am using the formula Flux = E*A, since the E vector is the same everywhere. Brief explanations of steps are appreciated!

Item 14 Part A In (Figure 1) take the half-cylinder's radius and length to be 3.4 cm and 15 cm, respectively. The half cylinder is "open" (the side which we aren't seeing in the figure does not have a cap), so that the field lines only pass through the object one time If the electric field has magnitude 5.3 kN/C, find the flux through the half-cylinder. Hint: You don't need to do an integral! Why not? Express your answer with the appropriate units Submit My Answers Give Up Figure 1 Incorrect; Try Again; 5 attempts remaining Continue

Explanation / Answer

Flux, phi = E x A = 5.3 x 103 x (0.15 x 2 x 0.034) = 54.06 Nm2/C

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