You were driving a car with velocity m/s. You quickly turned and braked, and you

Question

You were driving a car with velocity m/s. You quickly turned and braked, and your velocity became m/s. The mass of the car was 1100 kg. (a) what was the (vector) change in momentum Delta p during this maneuver? Pay attention to signs. Delta p = kg middot m/s (b) What was the (vector) impulse applied to the car? (vector) impulse: N middot s (c) If the maneuver took 6 seconds, what was the average (vector) force exerted on the car? (The net force is due to the ground and the Earth: the y components of these forces cancel.) F_net = N

Explanation / Answer

a)
V = Vf - Vi
= <15,0,24> - <21,0,18>
= <-6,0,6> m/s

P = m*V
= 1100 Kg <-6,0,6> m/s
= <-6600,0,6600> Kg.m/s

b)
impulse is change in momentum
so,
impulse = P = <-6600,0,6600> N.s

c)
F = impulse / time
= <-6600,0,6600> N.s / 6s
= <-1100,0,1100> N

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