1-D Kinematics Begin Date: 8/222016 1200:00 AM-Due Date: 912017 8:0000 AM Ead Da
ID: 1651129 • Letter: 1
Question
1-D Kinematics Begin Date: 8/222016 1200:00 AM-Due Date: 912017 8:0000 AM Ead Date: 12152017 11.59 00 PM (39) Problem 10: Gravitational acceleration on the moon is one sixth of that on Earth. A ball released from rest above the surface falls from height d in a time of t- 1.I seconds. heexpertta.com ted «P 25% Part (a) Write an expression for the final velocity v of the ball when it impacts the surface of the moon ass rest. This expression should be in terms of only, g (the gravitational acceleration on Earth), and time, t. a ng it s dropped fom 2596 Part (b) Calculate the final velocity, vy, numerically in m s. 25% Part (c) Calculate the height, d (in meters), from which the ball was dropped. Grade Sumnary Potential 100 pleted sinO cotan asin ac0 atan acotan sin 123 ial ial Degrees Radians Feedbacks daductson per feedback dedactice per hist Hats remanig a 259 Part (4) From how high up would this ball need to be dropped on the earth, d. (in meter),if it took the ame time to reach the His ground as it did on the moon?Explanation / Answer
Here ,
a) at moon g' = g/6
vf = gt/6
b)
vf = 9.8 * 1.1/6 = 1.8 m/s
c) for the height
h= 0.50 * g/6 * t^2
h = 0.50 * 9.8/6 * 1.1^2
h = 0.99 m
the height is 0.99 m
d)
for the ball at earth
h = 0.50 * g * t^2
h = 0.50 * 9.8 * 1.1^2
h = 5.9 m
the height will be 5.9 m on earth
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