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Suppose a 54-turn coil lies in the plane of the page in a uniform magnetic field

ID: 1649715 • Letter: S

Question

Suppose a 54-turn coil lies in the plane of the page in a uniform magnetic field that is directed out of the page. The coil originally has an area of 0.175 m2. It is stretched to have no area in 0.100 s. What is the magnitude (in V) and direction (as seen from above) of the average induced emf if the uniform magnetic field has a strength of 2.00 T? magnitude V direction---Select---clockwisecounterclockwiseThe magnitude is zero. Suppose a 54-turn coil lies in the plane of the page in a uniform magnetic field that is directed out of the page. The coil originally has an area of 0.175 m2. It is stretched to have no area in 0.100 s. What is the magnitude (in V) and direction (as seen from above) of the average induced emf if the uniform magnetic field has a strength of 2.00 T? magnitude V direction---Select---clockwisecounterclockwiseThe magnitude is zero. Suppose a 54-turn coil lies in the plane of the page in a uniform magnetic field that is directed out of the page. The coil originally has an area of 0.175 m2. It is stretched to have no area in 0.100 s. What is the magnitude (in V) and direction (as seen from above) of the average induced emf if the uniform magnetic field has a strength of 2.00 T? magnitude V direction---Select---clockwisecounterclockwiseThe magnitude is zero.

Explanation / Answer

change in flux=B*area=0.35

induced emf=number of turns*change in flux/time=18.9 /0.1=189 volts=189 V

for direction option must be given.We will select from the options given by the question asker.

normal direction=top to bottom

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