The flashlight is slowly turned away from the vertical direction. At what angle

Question

The flashlight is slowly turned away from the vertical direction. At what angle will the beam no longer be visible above the surface of the pool? Answer in units of degree A glass block having n = 1.35 and surrounded by air measures 7.7 cm times 7.7 cm. A ray has an angle of incidence of theta_1 = 47.1 degree on the top surface of the block. A certain concave spherical mirror has a focal length of 8.9 cm. Find the location of the image for an object distance of 19.4 cm. Answer in units of cm. What is the magnification for an object distance of 19.4 cm? Find the location of the image for an object distance of 6.06 cm. Answer in units of cm. Calculate the magnification for an object distance of 6.06 cm. q_1 = 2f q_1 = 1/2 f

Explanation / Answer

Part 1) Lens formula:

1/do + 1/di = 1/f

=> 1/19.4 + 1/di = 1/8.9

=> Image distance, di = 8.9 * 19.4 / (19.4 - 8.9) = 16.4 cm

Part 2) Magnification, m = -di/do = -16.4 / 19.4 = -0.845

Part 3) We have,

1/do + 1/di = 1/f

=> 1/6.06 + 1/di = 1/8.9

=> Image distance, di = 8.9 * 6.06 / (6.06 - 8.9) = -19.0 cm

Part 4) Magnification, m = -di/do = -(-19.0) / 6.06 = 3.135

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