A double slit aperture is illuminated with light of wavelength 600 nm. The figur

Question

A double slit aperture is illuminated with light of wavelength 600 nm. The figure shows the light intensity on a screen 2 m behind the slits. The central maximum occurs on the screen at location x = 2.5 cm. Find the path-length difference for the light that travels from the two slits to the screen location x = 4.5 cm. Find the path-length difference for the light that travels from the two slits to the screen location x = 3 cm. Include a sketch illustrating the concept of path-length difference. Fully justify your answers.

Explanation / Answer

at x=2.5, it is zero order maxima. at x= 3 , it is the first minima, so path defference should be lambda/2=(600/2)= 300 nm.

at x= 4.5, it is the second order maxima, so path difference should be 2lambda=[ 2*600 ] = 1200 nm.

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