See attached problem 11. According to the text g (free fall acceleration) = ag (
ID: 1649373 • Letter: S
Question
See attached problem 11. According to the text
g (free fall acceleration) = ag (gravitational acceleration) - w^2R (centripital acceleration). Also I know ag = GM/R2 and and w = 2Pi/T...
The answer according to the text is b = d= f > e > c > a.
I see why e > c > a since the larger T is the less the centripital accelleration will be.
I don't understand why b, d , and f at the poles are equal and greater than the rest of the points.. Is centripital acceleartion zero at the poles?
from the origin ow and what is the H3-28 UUestion g t is the 12 limit of the change? 10 Figure 13-29 shows six paths by 1 which a rocket orbiting a moon might 2 move from point a to point b. Rank the 3 paths according to (a) the correspon- ding change in the gravitational poten- tial energy of the rocket-moon system and (b) the net work done on the rocket by the gravitational force fromm the moon,greatest first. 11 Figure 13-30 shows three uniform spherical planets that are identical in size and mass. The periods of rotation T for the planets are given, and six lettered points are indicated-three points are on the equators of the planets and three points are on the north poles. Rank the points according to the value of the free-fall acek eration g at them, greatest first. Figure 13-29 Question 10 16 h 24 h 48 h Figure 13-30 Question 11. 12 In Fig, 13-31, a particle of mass m(which is not sho be moved from an infinite distance to one of the locations a, b, and c T s not of the three possible , areExplanation / Answer
The centripetal radius approaches zero as it goes near the poles and becomes zero on reaching the poles.And as a result of which centripetal acceleration I.e w^2r becomes zero.So that accounts for the result
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