A 535 pF capacitor is charged to 185 V and then quickly connected to a 195 mH in

Question

A 535 pF capacitor is charged to 185 V and then quickly connected to a 195 mH inductor.

Part A

Determine the frequency of oscillation.

Express your answer with the appropriate units.

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Correct

Part B

Determine the peak value of the current.

Express your answer with the appropriate units.

15.6 kHz

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Part C

Determine the maximum energy stored in the magnetic field of the inductor.

Express your answer with the appropriate units.

5.24•108 A

A 535 pF capacitor is charged to 185 V and then quickly connected to a 195 mH inductor.

Part A

Determine the frequency of oscillation.

Express your answer with the appropriate units.

SubmitMy AnswersGive Up

Correct

Part B

Determine the peak value of the current.

Express your answer with the appropriate units.

f =

15.6 kHz

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Incorrect; Try Again; 4 attempts remaining

Part C

Determine the maximum energy stored in the magnetic field of the inductor.

Express your answer with the appropriate units.

I =

5.24•108 A

U =

Explanation / Answer

A) f=1/{2pi x sqrt(L C)} = 15.6 kHz

C) Energy U = .5 C V^2 = 0.5(535 x 10^-12)(185)^2 = 9.16 x 10^-6 J

B) I=sqrt(2 U/L) = 9.69 x 10^-3 A or 9.69mA

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