t I Help Practice Assignment 2: Ch 16 Material Begin Date: 17 7:00:00 AM - -Due
ID: 1649312 • Letter: T
Question
t I Help Practice Assignment 2: Ch 16 Material Begin Date: 17 7:00:00 AM - -Due Date: 8/8/2017 11:59:00 PM End Date:8/9/2017 1:00:00 AM a1%) Problem 2: Consider two points in an electric field. The potential at point 1, v, is 38 V. The potential at point 2, V2, is 181 V. A proton is moved from point 1 to point 2. 33% Part (a) write an equation for the change of electric potential energy U of the proton in terms of the symbols given and the charge of the proton e. Potential 100% Attempts remaining: 10 4 5 6 per attempt) detailed view Hint I give up! Feedback: 0% deduction per feedback. Hints: deduction per hint. Hints remaining 33% Part (c) How much work is done by the electric force during the motion of the proton in J?Explanation / Answer
(a.) When the charge is moved in an electric field, it feels force which is called electric force, hence there is change in energy of that charged particle(proton in this case):
the equation for the same will be: V2-V1= del(U)/e --------> del(U)= [V2 -V1]*e
(b.) Using the above equation :
Charge on a proton is +1.602*10-19C which is =1eV .
Since there is only one proton moving in that electric field, so charge will remain to be 1 eV.
------> Change in electric potential energy : del(U)= (181-38)*1eV = 143 eV
(c) According to the work energy principle theorem:
On the expense of internal energy, work is done.
----> Work done in moving the charge from point 1 to 2 = -del(U)
= -143 eV
= -(143* 1.6* 10-19) Joules
W = - 2.28* 10-17 Joules
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