A capacitor C_1= 4.00 mu F is charged up to delta V = 100 Volt. Another capacito

Question

A capacitor C_1= 4.00 mu F is charged up to delta V = 100 Volt. Another capacitor C_2 = 4.00 mu F has no charge (see picture 5.1 below). Without discharging, C_1 is connected to C_2 (picture 5.2 below). a) What is the chare q on C_1 before both capacitors are connected? b) What is the energy U stored on C_1 before both capacitors are connected? c) (yes, it's very simple) What is the total charge q' = q_1+ q_2 after two capacitors connected? d) What is the new voltage AV" across both capacitors after the two are connected?

Explanation / Answer

charge on first capacitor q = c1v0 = 4*10^-6*100 = 4*10^-4 C

if two capacitors are connecte then new voltage is v = q/c1+c2

v = 4*10^-4/8*10^-6 = 100/2 = 50 V

charge on c1 is q1 = c1v = 4*10^-6*50 = 2*10^-4 C

charge on c2 is q2 = c2v = 4*10^-6*50 = 2*10^-4 C

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