A 2.00-nF capacitor with an initial charge of 4.39 mu C is discharged through a

Question

A 2.00-nF capacitor with an initial charge of 4.39 mu C is discharged through a 1.26-k Ohm resistor. (a) Calculate the current in the resistor 9.00 mu s after the resistor is connected across the terminals of the capacitor. (Let the positive direction of the current be define such that dQ/dt > 0.) 48.97 This is the correct magnitude of the current mA (b) what charge remains on the capacitor after 8.00 mu s? mu C (c) What is the (magnitude of the) maximum current in the resistor? 48.97 When is the current through the resistor at a maximum? A

Explanation / Answer

Q(t)=Qe^-t/RC

t/RC=9×10^-6/1.26×10^3×2×10^-9=3.57

I=-Q/RC e^-t/RC=-1.74e^-3.57=-0.048991A

Charge after 8×10^-6s

Q=4.39×10^-6e^-3.175

Q=0.18×10^-6C

Max current=1.74A

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