The conducting rod shown in the figure has length L, and is being pulled along h

Question

The conducting rod shown in the figure has length L, and is being pulled along horizontal, frictionless conducting rails at a constant velocity, v. (The rails are connected at the right end with a metal strip.) A uniform magnetic field B, directed out of the page, fills the region in which the rod moves. L = 20 cm, v = 30.0 m/s, and B = 2.0T. Assume the moving, conducting: rod has a resistance of 1.0 Ohm, but the rails and metal strip have much smaller resistance. a) What is the magnitude of the emf induced in the moving rod? b) What is the direction of this emf across the moving rod (up or down as viewed on the page? c) What is the magnitude of the current induced in the conducting loop? d) What is the direction of this current: clockwise or counterclockwise? e) At what rate is thermal energy being generated in the rod?

Explanation / Answer

A) induced emf = vLB

= 30*0.20*2

= 12 V answer

B) By lenz law current in rod should be in upward direction which makes lower end at higher potential than upper. So direction of emf is downward.

C) by ohms law, current i = V/R = 12/1 = 12 A answer

D) current through rod will be in upward direction by lenz law.

E) Rate = i^2 R = 12^2 *1 =144 W

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