vanquishing Magneto, Amy is back to her usual life: being an excellent trying to

Question

vanquishing Magneto, Amy is back to her usual life: being an excellent trying to complete her Obm's Law physics lab. Here is her circun now she is g8 3 V e most cCircuits, the physical length and width of the circuit do not matter at all, but Amy has a sinking feeling that later in this problem they will be necessary... a) First, determine the current Amy sbould expect to flow through the resistor. After being emburassed by bow casily Magneto defcated him, Bob is also back to his ustual life: being a bad physics student. So he is in the basement lab, irresponsibly exprimenting with large changing magnetic fields. It's getting out of control: he has created a magnetic field so powerful that it passes through the ceiling and into Amy's room. At the location of Amy's circuit, Bob's magnetic field is uniform in space but is increasing with time according to the following function- B(t) 0.05 The units work out so that if t is measured in seconds, B is in Teslas. The magnetic field is oriented so that it points into the page in Amy's diagram b) Determine the magnetic flux ,-/8-da through Amy's circuit, as a function of time. #BA : (0.05t 2)(0.4)(0.3) 0.00 2 o) Apply Faaday's Law to determine the magnitude of the induced emf, in volts,as a function of time. y's Law to determine the magnitude of the induced emf, in volts, as a function of time. dt dt d) Use your right hand and Lend's Law to find the direction of this emf. Describe it as counterclockwise (CCW) or clockwise (CW), relative to the diagram above. The direction of the induced urrent is ccw counter clock wise. imd the direchon of the emf is arso ccw

Explanation / Answer

Your answers seem to be correct. Great work

For the (g) part, if we place the voltmeter to the left means we are attaching it in parallel with the battery. So it should read 3 V which is the battery capacity.

For the (h) part, if we take your equation which you found in part (c)

E = 2(0.006)t

then, 2(0.006)t = 3 V

t = 3/2(0.006) = 250 seconds or around 4.167 minutes.

For (i) part, use the same equation as you did in part (e). If you are taking initial voltage as 3V and final also as 3 V, current will be zero.

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