u) At what speed would an electron have to travel (in a vacuum) to move of h o c
ID: 1648151 • Letter: U
Question
u) At what speed would an electron have to travel (in a vacuum) to move of h o cm in the magnetic field of the earth, 50 x 10 T (Recall that the mass of an electron only 9-11 x io" kg, and its charge equals 1.60x 30°C.) About in a circle with a radius of an electron is a. 1.14 m/s b. 88,000 m/s or 8.8x 10 m/s. c. 8,800,00o or 8.8 x 1o m/s. d. 88,000,0oo or 8.8 x10 m/s. 12) Electric line when they are working ne magnetic field. In which direction must the power lines by oriented for this to happen? maintenance workers sometimes can hear the electric power lines humming ar them, as the wires vibrate up and down ever so slightly in the earth's a. Any orientation will do, since the earth's field can be sensed everywhere. b. They must be oriented north and south. c. They must be oriented east and west. 13) A wooden wall for practicing tennis service at a park is 2.43 m high and 4.86 m wide. If at noon, when the sun is straight south, the sunlight passes along the wall parallel with it, what magnetic flux from the earth's magnetic field of s.o x 10 T passes through it? a. zero b. o.o000042 Wb of 4.2 x 10 Wb d. o.ooo59 Wb or 5.9 x 10 Wb A single loop of wire 1o cm high and 20 cm wide is situated half in and half out of a uniform magnetic field, xxx xX pointing into the page, of o.oo20 T. Use this information for the next three questions 14) As shown, the flux through the loop equals b. o.o00040 Wb or 4.0 x 10 Wb c. zero 15) The loop is now zipped to the right and leaves the field in 0000 sec, inducing a voltage of a. o.ooo0oo020 V or 2.0 x 10* v b. o.o20 V d. zero. 16) As the loop is leaving the field, the current induced in it flows a. c b. counter-clockwise. c.- not at all, no current flows.Explanation / Answer
Q11. Given:
radius of circle = r = 1 cm = 1 x 10-2 m
magnetic field of earth = B = 5 x 10-5 T
mass of electron = m =9.1 x 10-31 kg
charge of electron = q = 1.6 x 10-19 C
To find :
speed of electron = v=?
when electron travels in a circle in a magnetic field, the magnetic force = centripetal force
so, qvB=mv2/r
so, v= qrB/m = 1.6 x 10-19 x 1 x 10-2 x 5 x 10-5/(9.1 x 10-31) = 0.88 x 105 m/s =8.8 x 104 m/s
so speed of electron is 8.8 x 104 m/s
OPTION B IS THE CORRECT ANSWER
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