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FULL SCREEN PRINTER VERSION BACK Chapter 24, Problem 45 For one approach to this

ID: 1647565 • Letter: F

Question

FULL SCREEN PRINTER VERSION BACK Chapter 24, Problem 45 For one approach to this problem, consult Interactive LeaningWare 241. For each of the three sheets of polarizing material shown in the drawing, the orientation of the transmission axis is labeled relative to the vertical. The incident beam of light is unpolarized and has an intensity of 1460 W/m2. what is the intensity of the beam transmitted through the three sheets when 1-18.6°, 2-48.0°, and ' 99.90? Transmitted bean Vertical Incident beam de Units Number The number of significant digits is set to 3, the tolerance is +/-3% Click if you would like to show Work for this question: Open. Show.Work LINK TO TEXT Question Attempts: 0 of 5 used SAVE FOR LATIAQUBNLY ANDWILK SoI. All Rights Reserved. A Division oflahn Wss

Explanation / Answer

Here ,

for the final intensity tranmitted

final intensity of light transmitted

If = Io * cos^2(theta2 - theta1) * cos^2(theta3 - theta2) * 0.50

If = 0.50 * 1460 * cos^2(30 degree) * cos^2(51.9 degree)

If = 208.5 W/m^2

the final intensity is 208.5 W/m^2