SHM-Hooke\'s Law/6 Name: nature Section Part II. Data and Calculation Table 2 1.
ID: 1647555 • Letter: S
Question
SHM-Hooke's Law/6 Name: nature Section Part II. Data and Calculation Table 2 1. Calculate average (mean) At (s) of the three readings. 2. Get the period T-at (s)/10 (because you timed 10 periods). 3. Calculate period squared T* (s) by squaring the period T. M(g) M (kg) At 18.75 8.66 10:866-Soo 079.87 9.92 998 996 2 go .230 1.513 607 9,9 10. 1.50 ,357 -116 1.19 0 4. Graph T (s2) (on vertical axis) vs. M (kg) (horizontal axis). Perform a best fit line, read from your graph the intercept. 5. By squaring eq. (3) you get: 4 m2 6, Equation (4) states that T2 is proportional to M with as the slope and 3km, as 4n2 3 k the intercept 7. From your graph, read where the best-fit line intersects Y-axis, this value is your intercept Intercept= (unit?) 8. Equate the value of the intercept determined in Step 7 to 5pm, and solve for the value of the ma. In this evaluation consider the value of k obtained from previous graph. Show your calculation to get credit! ms (measured value)= o59 | N Sr4_. (unit?) (Calculated fromintercep)Explanation / Answer
In the 9 part you need to measure it experimentally then only we can answer 10 part i.e. Percentage error.
1) there will be always some difference in the value since springs are not aa ideal as we consider it in theory. They do not have that much restoring capacity which can be the source of error in the measurement of mass of spring.
2) T is measured by using 10 or more oscillations, it reduces the error in measurement as mean is always more accurate.
3) period is determined by using stopwatch i. e. Mass is allowed to vibrate and during each 10 oscilltions time is noted and then it is divided by 10
4) ideally time should be more accurate but since during measurements air friction is always there so it causes some error in measurement of time.
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