An eight turn coil encloses an elliptical area having a major axis of 40.0 cm an

Question

An eight turn coil encloses an elliptical area having a major axis of 40.0 cm and a minor axis of 30.0 cm (Fig. P19.23). The coil lies in the plane of the page and has a 6.45 A current flowing clockwise around it. If the coil is in a uniform magnetic field of 1.93 times 10^-4 T, directed toward the left of the page, what is the magnitude of the for que on the coil? Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. N middot m A copper wire is 7.00 m long and has a cross-sectional area of 1.00 times 10^-4 m^2. This wire forms a one turn loop in the shape of square and is then connected to a battery that applies a potential difference of 0.200 V. If the loop is placed in a uniform magnetic field of magnitude 0.500 T, what is the maximum for que that can act on it? The resistivity of copper is 1.7 times 10^-8 middot m. 294.2 Your response differs from the correct answer by more than 10%. Double check your calculations. N middot m

Explanation / Answer

9. given, number of turns, n = 8
major axis = 2a = 40cm
minor axis , 2b = 30 cm
area of ellipse = A = pi*a*b = pi*0.2*0.15 = 0.0942477 m^2
Current in coil, i = 6.45 A ( clockwise)
Magnetic field, B = 1.93*10^-4 T ( towards left )

Now torque on a current carrying coil of area A, turns n in magnetic field B and carrying current i is given by
t = NIAM sin(theta) ( where theta is the angle between the normal to the area and the magnetic field, so 90 degree in this case)
t = 8*6.45*0.0942477*1.93*10^-4 sin(90) = 9.385*10^-4 Nm

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