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There are three identical conducting spheres have charges as follows: sphere 1 i

ID: 1646153 • Letter: T

Question

There are three identical conducting spheres have charges as follows: sphere 1 is +3.0 Q, sphere 2 is -6.0 Q, and sphere 3 is +2.0 Q. First, sphere 1 is touched to sphere 2 and then sphere 2 to sphere 3 and then sphere 3 to sphere 1 then it is removed. What are the final charges for three charges? (A) Sphere 1 = -1.5 Q, sphere 2 = +1.0 Q, sphere 3 = -1.0 Q. (B) Sphere 1 = -1.5 Q, sphere 2 = +2.0 Q, sphere 3 = -0.5 Q. (C) Sphere 1 = -1.5 Q, sphere 2 = +0.5 Q, sphere 3 = -0.5 Q. (D) Sphere 1 = -0.5 Q, sphere 2 = +0.5 Q, sphere 3 = -0.5 Q. (E) Sphere 1 = -0.5 Q, sphere 2 = +1.0 Q, sphere 3 = -1.0 Q.

Explanation / Answer

when two spheres are touched and removed their charge is equally distributed, using this

when 1 and 2 are touched

Qnet = 3 - 6 = -3 Q

Q1 = Q2 = -1.5Q

then 2 and 3 are touched

Qnet = -1.5Q + 2Q = 0.5Q

Q2 = Q3 = 0.25Q

then 3 and 1 is touched

Qnet = -1.5Q + 0.25Q = -1.25Q

Q3 = Q1 = -0.625Q

None of the given options are correct,

Net charge = 3 - 6 + 2 = -1Q

Since net charge is conserved, So you can check by calculating net charge in each option, that none of the option is a match.

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