The shaded region in the diagram below is a region of uniform electric field tha

Question

The shaded region in the diagram below is a region of uniform electric field that is parallel to the horizontal direction (x-axis). A charge Q = -3.9 mu C moves through this region as shown by the green arrow. (a) If the charge accelerates as it moves from A to B, what is the direction of the electric field in this region? to the left to the right (b) The work done by the electric field as the charge moves from location A to location B is +1.50 times 10^-3 J. What is the potential difference V_B - V_A? V

Explanation / Answer

a ) charge moves from A to B so that direction of electric electric field to the left

b) vB - vA = W/q = 1.50*10-3 / 3.9*10-6 = 384.61 V

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