Thank you -- h 1Griffith( !Griffith c %Current Students COM 2-HONORS PHYSICS f)

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-- h 1Griffith( !Griffith c %Current Students COM 2-HONORS PHYSICS f) http://stemplosion.com/tetbook html server asp?htm stem as n.com took 1 serve as ?ht m BB Exercises and Videos PHYS100,53124, SUMMER.., x sno 53124-s nee.. x "22 unread-el he1337 bya.. "(229 unread)-elah 1337@ya CON 2-HONORS HYS S File Edit View Fevortes Tools Help Banking with Citi Cit double integral Wolfram. Visa Bulletin For February. Home-The Lib ary Enroling in Clesses 2 Nin e Install cr Update craigsist san dieqojobs, e.. bmi.ir bel du San Diego Loans, Auto Lo Problem ID GriffithChapter07 15 Enter your 7 digit student id#: Student ecognized AVmeans your answer is correct STEMplosion Complimentary Calculator Welcome to the Astro-Physical Calculator mcans your answer is wrong A Xmeans your answer is close but wrong (do not round off at all unless stated) Press the SUBMIT YOUR ANSWER(S) button, to save and send your work to your irnstructor, when you complete o partially complete tis exercise Units: SI For this problem, five railroad cars each have a mass of 13,000 kg Four connected railroad cars sit at rest on a track. The fifth car approaches them with a vclocity of 17 m/s. The fifth car collides and couples with the other four cars (a) What is the momentum of the fifth car before the collision? (b) What is the momentum of all the cars after the coupling? (e What is the velocity of the five coupled cas after the colision? (d) What is the intial kinetic energy of the fifth before the collision? (e) What is the kinetic emergy of all five cas just after the collision? () Is energy conserved in the collision? sin asin cos acos tan atan 1/x xBksp MIR Mt MR2 M2t Pat Units gms kg ms n s Physical Constants Hint Astronomical Constants AU Sun T T sun Hint Planetary Data Mercury m yes or no Submit Your A Cancel 955 PM

Explanation / Answer

a)momentum of fifth car before collision = mass x velocity = 13000*17 = 221000 kg-m/s

b)From conservation of momentum, momentum of all the cars after collision will be equal to initial momentum = 221000kg-m/s

c)velcoti of five coupled cars = momentum/mass of coupled cars = 221000/(5*13000) = 3.4 m/s

d)initial kinetic energy of fifth car = (1/2)mv2 = (1/2)*13000*172 = 1878500 Joules

e)kinetic energy of all cars just after collision = (1/2)*5*13000*3.42 = 375700 Joules

f)No, the energy is not conserved because the kinetic energy reduces after collision

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