All 3 incorrect S 211-Summer17-STINNETT Activities and Due Dates I HW Potential

Question

All 3 incorrect S 211-Summer17-STINNETT Activities and Due Dates I HW Potential Energy and Energy Conservation 7/17/2017 10:00 PM 71.7/100 PrintCalculator Periodic Table estion 14 of 14 Sapling Learning A seasoned mini golfer is trying to make par on a tricky hole #5. The golfer can complete the hole by hitting the ball from the flat section it lays on, up a 45 ramp, and launching the ball into the hole which is d 2.20 m away from the end of the ramp. If the opening of the hole and the end of the ramp are at the same height, y 0.810 m, at what speed must the golfer hit the ball to launch the ball over the moat so that it lands directly in the hole? Assume a frictionless surface (so the ball slides without rotating). The acceleration due to gravity is 9.81 m/s2 2.20 m Number 22.3 m/s 0.810 m 45*

Explanation / Answer

Velocity needed at the end of incline = v

Range = v^2 sin 2theta /g = v^2 sin 90 degree /9.81

2.20 = v^2 /9.81

v = sqrt (9.81*2.20) = 4.6456 m/s

Speed of hitting u = sqrt (v^2 + 2gh)

= sqrt (4.6456^2 +2 *9.81*0.810)

= 6.12 m/s answer

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